In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a red and a black card, and the last one contains two black cards. An envelope is selected at random and a card is withdrawn and found to be red. What is the chance the other card is black?

Answer:[tex]\frac{2}{5}[/tex]Step-by-step explanation:3 envelopes having 2 red card 2 envelopes having 1 red card and 1 black card1 envelope having 2 black cards We are given that . An envelope is selected at random and a card is withdrawn and found to be red.So, No. of ways of envelope having red card = 3+2 = 5No. of required ways of envelope having 1 red card and 1 black card = 2So, probability of getting an envelope having 1 red card and 1 black card = [tex]\frac{2}{5}[/tex]Hence The chance the other card is black is [tex]\frac{2}{5}[/tex]