If Zach has 4 times as many dimes as quarters and they have a combined value of 455 cents, how many of each coins does he have?

ANSWER: Zach has 28 dimes and 7 quarters. SOLUTION: Given, Zach has 4 times as many dimes as quarters  And they have a combined value of 455 cents,  We need to find how many of each coins does he have? Let, the number of dimes be x and number of quarters be y. Then, x = 4y → (1) Total combined value = 455 cents x(value of one dime) + y(value of one quarter) = 455 cents x(10 cents) + x(25 cents) = 455 cents 10x + 25y = 455 → (2) Now, substitute (1) in (2) 10(4y) + 25y = 455 40x + 25y = 455 65y = 455 y = 7 substitute y value in (1) x = 4(7)  = 28 Hence, zach has 28 dimes and 7 quarters.